0=x^2-60x+49

Solution for 0=x^2-60x+49 equation:

0=x^2-60x+49

We move all terms to the left:

0-(x^2-60x+49)=0

We add all the numbers together, and all the variables

-(x^2-60x+49)=0

We get rid of parentheses

-x^2+60x-49=0

We add all the numbers together, and all the variables

-1x^2+60x-49=0

a = -1; b = 60; c = -49;
Δ = b2-4ac
Δ = 602-4·(-1)·(-49)
Δ = 3404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3404}=\sqrt{4*851}=\sqrt{4}*\sqrt{851}=2\sqrt{851}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{851}}{2*-1}=\frac{-60-2\sqrt{851}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{851}}{2*-1}=\frac{-60+2\sqrt{851}}{-2}
$